Learning Objectives

  • Describe the purpose of the dplyr and tidyr packages.
  • Select certain columns in a data frame with the dplyr function select().
  • Select certain rows in a data frame according to filtering conditions with the dplyr function filter().
  • Link the output of one dplyr function to the input of another function with the ‘pipe’ operator %>%.
  • Add new columns to a data frame that are functions of existing columns with mutate().
  • Use the split-apply-combine concept for data analysis.
  • Use summarize(), group_by(), and count() to split a data frame into groups of observations, apply summary statistics for each group, and then combine the results.
  • Describe the concept of a wide and a long table format and for which purpose those formats are useful.
  • Describe what key-value pairs are.
  • Reshape a data frame from long to wide format and back with the pivot_wider() and pivot_longer() commands from the tidyr package.
  • Export a data frame to a .csv file.

Open Project

Open your Environmental Data Analysis project, and create a new script named “A6_DataWrangling”.

Data Wrangling using dplyr and tidyr

Bracket subsetting is handy, but it can be cumbersome and difficult to read, especially for complicated operations. Enter dplyr. dplyr is a package for making tabular data wrangling easier. It pairs nicely with tidyr, which enables you to swiftly convert between different data formats for plotting and analysis.

Packages in R are basically sets of additional functions that let you do more stuff. The functions we’ve been using so far, like str() or data.frame(), come built into R; packages give you access to more of them. Before you use a package for the first time you need to install it on your machine, and then you should import it in every subsequent R session when you need it. We have already installed the tidyverse package. This is an “umbrella-package” that installs several packages useful for data analysis which work together well such as tidyr, dplyr, ggplot2, tibble, etc.

The tidyverse package tries to address 3 common issues that arise when doing data analysis with some of the functions that come with R:

  1. The results from a base R function sometimes depend on the type of data.
  2. Using R expressions in a non standard way, which can be confusing for new learners.
  3. Hidden arguments, having default operations that new learners are not aware of.

To load the package type:

# load the tidyverse packages, including dplyr
library(tidyverse)

What are dplyr and tidyr?

The package dplyr provides easy tools for the most common data wrangling tasks. It is built to work directly with data frames, with many common tasks optimized by being written in a compiled language (C++). An additional feature is the ability to work directly with data stored in an external database. The benefits of doing this are that the data can be managed natively in a relational database, queries can be conducted on that database, and only the results of the query are returned.

This addresses a common problem with R in that all operations are conducted in-memory and thus the amount of data you can work with is limited by available memory. The database connections essentially remove that limitation in that you can connect to a database of many hundreds of GB, conduct queries on it directly, and pull back into R only what you need for analysis. This includes “big data” datasets as well as spatial data.

The package tidyr addresses the common problem of wanting to reshape your data for plotting and use by different R functions. Sometimes we want data sets where we have one row per measurement. Sometimes we want a data frame where each measurement type has its own column, and rows are instead more aggregated groups - like plots or aquaria. Moving back and forth between these formats is nontrivial, and tidyr gives you tools for this and more sophisticated data reshaping.

To learn more about dplyr and tidyr after the workshop, or to refresh your memory in the future, you may consult the cheatsheets for dplyr and tidyr available on the course Brightspace page.

We’ll read in our data using the read_csv() function, from the tidyverse package readr, instead of read.csv(). If you do not have the data_raw folder with the data that we set up earlier in the semester, you can access the “portal_data_joined.csv” data directly from the course Brightspace page and set up a new data_raw folder.

# Import data file
surveys <- read_csv("data_raw/portal_data_joined.csv")
## Rows: 34786 Columns: 13
## ── Column specification ────────────────────────────────────────────────────────
## Delimiter: ","
## chr (6): species_id, sex, genus, species, taxa, plot_type
## dbl (7): record_id, month, day, year, plot_id, hindfoot_length, weight
## 
## ℹ Use `spec()` to retrieve the full column specification for this data.
## ℹ Specify the column types or set `show_col_types = FALSE` to quiet this message.
# Inspect the data
str(surveys)
# Call data table as a new tab
View(surveys)

Notice that the class of the data is tbl_df.

This is referred to as a “tibble”. Tibbles tweak some of the behaviors of the data frame objects we introduced in the “Starting with Data” workshop. The data structure is very similar to a data frame. For our purposes the only differences are that:

  1. In addition to displaying the data type of each column under its name, it only prints the first few rows of data and only as many columns as fit on one screen.
  2. Columns of class character are never converted into factors.

We’re going to learn some of the most common dplyr functions:

  • select(): subset columns
  • filter(): subset rows on conditions
  • mutate(): create new columns by using information from other columns
  • group_by() and summarize(): create summary statistics on grouped data
  • arrange(): sort results
  • count(): count discrete values

Selecting columns and filtering rows

To select columns of a data frame, use select(). The first argument to this function is the data frame surveys, and the subsequent arguments are the columns to keep.

select(surveys, plot_id, species_id, weight)

To select all columns except certain ones, put a “-” in front of the variable to exclude it.

select(surveys, -record_id, -species_id)

This will select all the variables in surveys except record_id and species_id.

To choose rows based on a specific criterion, use filter().

filter(surveys, year == 1995)

Pipes

What if you want to select and filter at the same time? There are three ways to do this: use intermediate steps, nested functions, or pipes.

With intermediate steps, you create a temporary data frame and use that as input to the next function, like this:

surveys2 <- filter(surveys, weight < 5)
surveys_sml <- select(surveys2, species_id, sex, weight)

This is readable, but can clutter up your work space with lots of objects that you have to name individually. (I also tend to run out of creativity after two or three object names.) With multiple steps, all the new object names can also be hard to keep track of.

You can also nest functions (i.e., one function inside of another), like this:

surveys_sml <- select(filter(surveys, weight < 5), species_id, sex, weight)

This is handy, but can be difficult to read if too many functions are nested, as R evaluates the expression from the inside out (in this case, filtering, then selecting).

The last option, pipes, is a more recent addition to R. Pipes let you take the output of one function and send it directly to the next, which is useful when you need to do many things to the same dataset. Pipes in R look like %>% and are made available via the magrittr package, installed automatically with dplyr. If you use RStudio, you can type the pipe with Ctrl + Shift + M if you have a PC or Cmd + Shift + M if you have a Mac.

surveys %>% 
  filter(weight < 5) %>% 
  select(species_id, sex, weight)

In the above code, we use the pipe to send the surveys dataset first through filter() to keep rows where weight is less than 5, then through select() to keep only the species_id, sex, and weight columns. Since %>% takes the object on its left and passes it as the first argument to the function on its right, we don’t need to explicitly include the data frame as an argument to the filter() and select() functions any more.

Some may find it helpful to read the pipe like the word “then”. For instance, in the above example, we took the data frame surveys, then we filtered for rows with weight < 5, then we selected columns species_id, sex, and weight. The dplyr functions by themselves are somewhat simple, but by combining them into linear workflows with the pipe, we can accomplish more complex wrangling of data frames.

If we want to create a new object with this smaller version of the data, we can assign it a new name:

# Create new tibble object
surveys_sml <- surveys %>%
  filter(weight < 5) %>%
  select(species_id, sex, weight)

# View first few rows of new tibble
head(surveys_sml)
## # A tibble: 6 × 3
##   species_id sex   weight
##   <chr>      <chr>  <dbl>
## 1 PF         F          4
## 2 PF         F          4
## 3 PF         M          4
## 4 RM         F          4
## 5 RM         M          4
## 6 PF         <NA>       4

Note that the final data frame is the leftmost part of this expression.

Challenge 1

Using pipes, subset the surveys data to include animals collected before 1995 and retain only the columns year, sex, and weight. Save the new tibble as an object named surveys_1995.
How many columns are in the surveys_1995 tibble?
How many rows are in the surveys_1995 tibble?

Answer 
# Create new tibble
surveys_1995 <- surveys %>% 
  filter(year < 1995) %>% 
  select(year, sex, weight)
# Inspect tibble
str(surveys_1995)
## tibble [21,486 × 3] (S3: tbl_df/tbl/data.frame)
##  $ year  : num [1:21486] 1977 1977 1977 1977 1977 ...
##  $ sex   : chr [1:21486] "M" "M" NA NA ...
##  $ weight: num [1:21486] NA NA NA NA NA NA NA NA 218 NA ...

Mutate

Frequently you’ll want to create new “calculated” columns based on the values in existing columns, for example to do unit conversions, or to find the ratio of values in two columns. For this we’ll use mutate().

To create a new column of weight in kg:

surveys %>% 
  mutate(weight_kg = weight / 1000)

You can also create a second new column based on the first new column within the same call of mutate():

surveys %>%
  mutate(weight_kg = weight / 1000,
         weight_lb = weight_kg * 2.2)

If this runs off your screen and you just want to see the first few rows, you can use a pipe to view the head() of the data. (Pipes work with non-dplyr functions, too, as long as the dplyr or magrittr package is loaded).

surveys %>%
  mutate(weight_kg = weight / 1000) %>%
  head()

The first few rows of the output are full of NAs, so if we wanted to remove those we could insert a filter() in the chain:

surveys %>%
  filter(!is.na(weight)) %>%
  mutate(weight_kg = weight / 1000) %>%
  head()

is.na() is a function that determines whether something is an NA. The ! symbol negates the result, so we’re asking for every row where weight is not an NA.

Challenge 2

Create a new data frame from the surveys data that meets the following criteria: contains only the species_id column and a new column called hindfoot_half containing values that are half the hindfoot_length values. In this hindfoot_half column, there are no NAs and all values are less than 30.

Hint: think about how the commands should be ordered to produce this data frame!

How many columns are in your new dataframe?
How many rows are in your new dataframe?
What type of variable is species_id?

Answer 
# either
surveys_hindfoot_half <- surveys %>% 
  mutate(hindfoot_half = hindfoot_length / 2) %>% 
  filter(!is.na(hindfoot_half)) %>% 
  filter(hindfoot_half < 30) %>% 
  select(species_id, hindfoot_half)

# or
surveys_hindfoot_half <- surveys %>%
    filter(!is.na(hindfoot_length)) %>%
    mutate(hindfoot_half = hindfoot_length / 2) %>%
    filter(hindfoot_half < 30) %>%
    select(species_id, hindfoot_half)

# inspect new data frame
str(surveys_hindfoot_half)
## tibble [31,436 × 2] (S3: tbl_df/tbl/data.frame)
##  $ species_id   : chr [1:31436] "NL" "NL" "NL" "NL" ...
##  $ hindfoot_half: num [1:31436] 16 15.5 16 17 16 16.5 16 16 16.5 15 ...

Split-apply-combine data

Many data analysis tasks can be approached using the split-apply-combine paradigm: split the data into groups, apply some analysis to each group, and then combine the results. dplyr makes this very easy through the use of the group_by() function.

Summarizing

group_by() is often used together with summarize(), which collapses each group into a single-row summary of that group. group_by() takes as arguments the column names that contain the categorical variables for which you want to calculate the summary statistics. So to compute the mean weight by sex:

surveys %>% 
  group_by(sex) %>% 
  summarize(mean_weight = mean(weight, na.rm = T))

You may also have noticed that the output from these calls doesn’t run off the screen anymore. It’s one of the advantages of tbl_df over data frame.

You can also group by multiple columns:

surveys %>% 
  group_by(sex, species_id) %>% 
  summarize(mean_weight = mean(weight, na.rm = T))

When grouping both by sex and species_id, the last few rows are for animals that escaped before their sex and body weights could be determined. You may notice that the last column does not contain NA but NaN (which refers to “Not a Number”). To avoid this, we can remove the missing values for weight before we attempt to calculate the summary statistics on weight. Because the missing values are removed first, we can omit na.rm = TRUE when computing the mean:

surveys %>%
  filter(!is.na(weight)) %>%
  group_by(sex, species_id) %>%
  summarize(mean_weight = mean(weight))

Here, again, the output from these calls doesn’t run off the screen anymore. If you want to display more data, you can use the print() function at the end of your chain with the argument n specifying the number of rows to display:

surveys %>%
  filter(!is.na(weight)) %>%
  group_by(sex, species_id) %>%
  summarize(mean_weight = mean(weight)) %>% 
  print(n = 64)

Once the data are grouped, you can also summarize multiple variables at the same time (and not necessarily on the same variable). For instance, we could add a column indicating the minimum weight for each species for each sex:

surveys %>%
  filter(!is.na(weight)) %>%
  group_by(sex, species_id) %>%
  summarize(mean_weight = mean(weight),
            min_weight = min(weight))

It is sometimes useful to rearrange the result of a query to inspect the values. For instance, we can sort on min_weight to put the lighter species first:

surveys %>%
  filter(!is.na(weight)) %>%
  group_by(sex, species_id) %>%
  summarize(mean_weight = mean(weight),
            min_weight = min(weight)) %>%
  arrange(min_weight)

To sort in descending order, we need to add the desc() function. If we want to sort the results by decreasing order of mean weight:

surveys %>%
  filter(!is.na(weight)) %>%
  group_by(sex, species_id) %>%
  summarize(mean_weight = mean(weight),
            min_weight = min(weight)) %>%
  arrange(desc(mean_weight))

Counting

When working with data, we often want to know the number of observations found for each factor or combination of factors. For this task, dplyr provides count(). For example, if we wanted to count the number of rows of data for each sex, we would do:

surveys %>% 
  count(sex)

The count() function is shorthand for something we’ve already seen: grouping by a variable, and summarizing it by counting the number of observations in that group. In other words, surveys %>% count() is equivalent to:

surveys %>%
    group_by(sex) %>%
    summarize(count = n())

For convenience, count() provides the sort argument:

surveys %>% 
  count(sex, sort = T)

Previous example shows the use of count() to count the number of rows/observations for one factor (i.e., sex). If we wanted to count combination of factors, such as sex and species, we would specify the first and the second factor as the arguments of count():

surveys %>% 
  count(sex, species)

With the above code, we can proceed with arrange() to sort the table according to a number of criteria so that we have a better comparison. For instance, we might want to arrange the table above in (i) an alphabetical order of the levels of the species and (ii) in descending order of the count:

surveys %>%
  count(sex, species) %>%
  arrange(species, desc(n))

From the table above, we may learn that, for instance, there are 75 observations of the albigula species that are not specified for its sex (i.e., NA).

Challenge 3

1. How many animals were caught in each plot_type surveyed?

Answer 
surveys %>% 
  count(plot_type)
## # A tibble: 5 × 2
##   plot_type                     n
##   <chr>                     <int>
## 1 Control                   15611
## 2 Long-term Krat Exclosure   5118
## 3 Rodent Exclosure           4233
## 4 Short-term Krat Exclosure  5906
## 5 Spectab exclosure          3918

2. Use group_by() and summarize() to find the mean, min, and max hindfoot length for each species (using species_id). Also add the number of observations (hint: see ?n).
What are the values for the first two species?

Answer 
surveys %>% 
  filter(!is.na(hindfoot_length)) %>% 
  group_by(species_id) %>%
  summarize(mean_hindfoot_length = mean(hindfoot_length),
            min_hindfoot_length = min(hindfoot_length),
            max_hindfoot_length = max(hindfoot_length),
            n = n())
## # A tibble: 25 × 5
##    species_id mean_hindfoot_length min_hindfoot_length max_hindfoot_length     n
##    <chr>                     <dbl>               <dbl>               <dbl> <int>
##  1 AH                         33                    31                  35     2
##  2 BA                         13                     6                  16    45
##  3 DM                         36.0                  16                  50  9972
##  4 DO                         35.6                  26                  64  2887
##  5 DS                         49.9                  39                  58  2132
##  6 NL                         32.3                  21                  70  1074
##  7 OL                         20.5                  12                  39   920
##  8 OT                         20.3                  13                  50  2139
##  9 OX                         19.1                  13                  21     8
## 10 PB                         26.1                   2                  47  2864
## # ℹ 15 more rows

3. What was the heaviest animal measured in each year?
Return the columns year, genus, species_id, and weight.
Based on your new tibble, what was the species_id for the heaviest animal in 1977?
Based on your new tibble, what was the species_id for the heaviest animal in 1979?

Answer 
surveys %>%
    filter(!is.na(weight)) %>%
    group_by(year) %>%
    filter(weight == max(weight)) %>%
    select(year, genus, species_id, weight) %>%
    arrange(year)
## # A tibble: 27 × 4
## # Groups:   year [26]
##     year genus     species_id weight
##    <dbl> <chr>     <chr>       <dbl>
##  1  1977 Dipodomys DS            149
##  2  1978 Neotoma   NL            232
##  3  1978 Neotoma   NL            232
##  4  1979 Neotoma   NL            274
##  5  1980 Neotoma   NL            243
##  6  1981 Neotoma   NL            264
##  7  1982 Neotoma   NL            252
##  8  1983 Neotoma   NL            256
##  9  1984 Neotoma   NL            259
## 10  1985 Neotoma   NL            225
## # ℹ 17 more rows

Reshaping with pivot_longer() and pivot_wider()

In the spreadsheet lesson, we discussed how to structure our data leading to the four rules defining a tidy dataset:

  1. Each variable has its own column
  2. Each observation has its own row
  3. Each value must have its own cell
  4. Each type of observational unit forms a table

Here we examine the fourth rule: Each type of observational unit forms a table.

In surveys, the rows of surveys contain the values of variables associated with each record (the unit), values such as the weight or sex of each animal associated with each record. What if instead of comparing records, we wanted to compare the different mean weight of each species between plots? (Ignoring plot_type for simplicity).

We’d need to create a new table where each row (the unit) is comprised of values of variables associated with each plot. In practical terms this means the values of the species in genus would become the names of column variables and the cells would contain the values of the mean weight observed on each plot.

Having created a new table, it is therefore straightforward to explore the relationship between the weight of different species within, and between, the plots. The key point here is that we are still following a tidy data structure, but we have reshaped the data according to the observations of interest: average species weight per plot instead of recordings per date.

The opposite transformation would be to transform column names into values of a variable.

We can do both these of transformations with two tidyr functions, pivot_wider() and pivot_longer().

Pivot wider

pivot_wider() takes three principle arguments:

  1. the data
  2. names_from, which specifies the column variable whose values will become new column names
  3. values_from, which specifies the column variable whose values will fill the new column variables

Further arguments include values_fill, which, if set, fills in missing values with the value provided (e.g. 0 or NA).

Let’s use pivot_wider() to transform surveys to find the mean weight of each species in each plot over the entire survey period. We use filter(), group_by() and summarise() to filter our observations and variables of interest, and create a new variable for the mean_weight. We use the pipe as before too.

surveys_gw <- surveys %>%
  filter(!is.na(weight)) %>%
  group_by(genus, plot_id) %>%
  summarize(mean_weight = mean(weight))

head(surveys_gw)
## # A tibble: 6 × 3
## # Groups:   genus [1]
##   genus   plot_id mean_weight
##   <chr>     <dbl>       <dbl>
## 1 Baiomys       1        7   
## 2 Baiomys       2        6   
## 3 Baiomys       3        8.61
## 4 Baiomys       5        7.75
## 5 Baiomys      18        9.5 
## 6 Baiomys      19        9.53

This yields surveys_gw where the observations for each plot are spread across multiple rows, 196 observations of 3 variables. If we use pivot_wider() to create a new column for each genus, containing values from mean_weight this becomes 24 observations of 11 variables, one row for each plot. We again use pipes:

surveys_wide <- surveys_gw %>%
  pivot_wider(names_from = "genus", values_from = "mean_weight")

head(surveys_wide)
## # A tibble: 6 × 11
##   plot_id Baiomys Chaetodipus Dipodomys Neotoma Onychomys Perognathus Peromyscus
##     <dbl>   <dbl>       <dbl>     <dbl>   <dbl>     <dbl>       <dbl>      <dbl>
## 1       1    7           22.2      60.2    156.      27.7        9.62       22.2
## 2       2    6           25.1      55.7    169.      26.9        6.95       22.3
## 3       3    8.61        24.6      52.0    158.      26.0        7.51       21.4
## 4       5    7.75        18.0      51.1    190.      27.0        8.66       21.2
## 5      18    9.5         26.8      61.4    149.      26.6        8.62       21.4
## 6      19    9.53        26.4      43.3    120       23.8        8.09       20.8
## # ℹ 3 more variables: Reithrodontomys <dbl>, Sigmodon <dbl>, Spermophilus <dbl>

We may wish to fill in the missing values using values_fill = 0.

surveys_gw %>%
  pivot_wider(names_from = "genus", values_from = "mean_weight", values_fill = 0) %>% 
  head()

Pivot longer

The opposing situation could occur if we had been provided with data in the form of surveys_wide, where the genus names are column names, but we wish to treat them as values of a genus variable instead.

In this situation we are gathering the column names and turning them into a pair of new variables. One variable represents the column names as values, and the other variable contains the values previously associated with the column names.

pivot_longer() takes four principal arguments:

  1. the data
  2. names_to, specifying the new variable we wish to create from column names
  3. values_to, specifying the new variable we wish to create and fill with values associated with the column names
  4. the columns that are wide that you wish to be long; you can specify these by name or number, or use a minus sign - to exclude columns

To recreate surveys_gw from surveys_wide we would create a new column called genus and a value column called mean_weight and pivot all columns except plot_id (or columns 2 through 11). Here we drop plot_id column with a minus sign.

# Pivot all columns except plot_id
surveys_long <- surveys_wide %>%
  pivot_longer(names_to = "genus", values_to = "mean_weight", -plot_id)

head(surveys_long)
## # A tibble: 6 × 3
##   plot_id genus       mean_weight
##     <dbl> <chr>             <dbl>
## 1       1 Baiomys            7   
## 2       1 Chaetodipus       22.2 
## 3       1 Dipodomys         60.2 
## 4       1 Neotoma          156.  
## 5       1 Onychomys         27.7 
## 6       1 Perognathus        9.62

Note that now the NA genera are included in the re-gathered format. Pivoting wider and then pivoting longer can be a useful way to balance out a dataset so every replicate has the same composition.

We could also have used a specification for what columns to include. This can be useful if you have a large number of identifying columns, and it’s easier to specify what to pivot than what to leave alone. And if the columns are in a row, we don’t even need to list them all out. Just use the : operator! You can refer to columns by name or by column number.

# Pivot columns by name
surveys_wide %>% 
  pivot_longer(names_to = "genus", values_to = "mean_weight", Baiomys:Spermophilus) %>% 
  head()
# Pivot columns 2 through 11
surveys_wide %>%
  pivot_longer(names_to = "genus", values_to = "mean_weight", 2:11) %>% 
  head()
## # A tibble: 6 × 3
##   plot_id genus       mean_weight
##     <dbl> <chr>             <dbl>
## 1       1 Baiomys            7   
## 2       1 Chaetodipus       22.2 
## 3       1 Dipodomys         60.2 
## 4       1 Neotoma          156.  
## 5       1 Onychomys         27.7 
## 6       1 Perognathus        9.62

Challenge 4

1.Pivot the surveys data frame wider, with year as columns, plot_id as rows, and the number of genera per plot as the values. You will need to summarize before reshaping, and use the function n_distinct() to get the number of unique genera within a particular chunk of data. It’s a powerful function! See ?n_distinct for more. Save your new data frame as object rich_time.
How many rows are in your data frame?
How many columns are in your data frame?
How many genera were present in plot 1 in 1985?

Answer 
# Create new data frame
rich_time <- surveys %>% 
  group_by(year, plot_id) %>% 
  summarize(n_genera = n_distinct(genus)) %>% 
  pivot_wider(names_from = "year", values_from = "n_genera")
# View new data frame
rich_time
## # A tibble: 24 × 27
##    plot_id `1977` `1978` `1979` `1980` `1981` `1982` `1983` `1984` `1985` `1986`
##      <dbl>  <int>  <int>  <int>  <int>  <int>  <int>  <int>  <int>  <int>  <int>
##  1       1      2      3      4      7      5      6      7      6      4      3
##  2       2      6      6      6      8      5      9      9      9      6      4
##  3       3      5      6      4      6      6      8     10     11      7      6
##  4       4      4      4      3      4      5      4      6      3      4      3
##  5       5      4      3      2      5      4      6      7      7      3      1
##  6       6      3      4      3      4      5      9      9      7      5      6
##  7       7      3      1      3      1      1      4      2      3      4      3
##  8       8      2      4      3      5      6      6      4      6      4      3
##  9       9      3      3      3      4      5      6      7      4      5      3
## 10      10      1     NA      2      5      5      8      4      2      3      1
## # ℹ 14 more rows
## # ℹ 16 more variables: `1987` <int>, `1988` <int>, `1989` <int>, `1990` <int>,
## #   `1991` <int>, `1992` <int>, `1993` <int>, `1994` <int>, `1995` <int>,
## #   `1996` <int>, `1997` <int>, `1998` <int>, `1999` <int>, `2000` <int>,
## #   `2001` <int>, `2002` <int>

2. Now take that data frame and pivot_longer(), so each row is a unique plot_id by year combination.
How many rows are in the data frame?
How many columns are in the data frame?

Answer 
rich_time %>% 
  pivot_longer(names_to = "year", values_to = "n_genera", -plot_id)
## # A tibble: 624 × 3
##    plot_id year  n_genera
##      <dbl> <chr>    <int>
##  1       1 1977         2
##  2       1 1978         3
##  3       1 1979         4
##  4       1 1980         7
##  5       1 1981         5
##  6       1 1982         6
##  7       1 1983         7
##  8       1 1984         6
##  9       1 1985         4
## 10       1 1986         3
## # ℹ 614 more rows

3.The surveys data set has two measurement columns: hindfoot_length and weight. This makes it difficult to do things like look at the relationship between mean values of each measurement per year in different plot types. Let’s walk through a common solution for this type of problem. First, use pivot_longer() to create a dataset where we have a name column called measurement that specifies the type of measurement and a value column that takes on the value of either hindfoot_length or weight. Hint: You’ll need to specify which columns are being gathered. Save your new dataframe as object surveys_long.
How many rows are in the surveys_long data frame?
How many columns are in the surveys_long data frame?

Answer 
# Create data frame
surveys_long <- surveys %>% 
  pivot_longer(names_to = "measurement", values_to = "value", c(hindfoot_length, weight))
#View data frame
surveys_long
## # A tibble: 69,572 × 13
##    record_id month   day  year plot_id species_id sex   genus   species  taxa  
##        <dbl> <dbl> <dbl> <dbl>   <dbl> <chr>      <chr> <chr>   <chr>    <chr> 
##  1         1     7    16  1977       2 NL         M     Neotoma albigula Rodent
##  2         1     7    16  1977       2 NL         M     Neotoma albigula Rodent
##  3        72     8    19  1977       2 NL         M     Neotoma albigula Rodent
##  4        72     8    19  1977       2 NL         M     Neotoma albigula Rodent
##  5       224     9    13  1977       2 NL         <NA>  Neotoma albigula Rodent
##  6       224     9    13  1977       2 NL         <NA>  Neotoma albigula Rodent
##  7       266    10    16  1977       2 NL         <NA>  Neotoma albigula Rodent
##  8       266    10    16  1977       2 NL         <NA>  Neotoma albigula Rodent
##  9       349    11    12  1977       2 NL         <NA>  Neotoma albigula Rodent
## 10       349    11    12  1977       2 NL         <NA>  Neotoma albigula Rodent
## # ℹ 69,562 more rows
## # ℹ 3 more variables: plot_type <chr>, measurement <chr>, value <dbl>

4. With this new data set, calculate the average of each measurement in each year for each different plot_type. Then pivot_wider() into a data set with a column for hindfoot_length and weight. Hint: You only need to specify the names_from and values_from columns for pivot_wider().
How many rows are in the new data frame?
How many columns are in the new data frame?
What was the mean weight of individuals captured in control plots in 1978?

Answer 
surveys_long %>% 
  group_by(year, measurement, plot_type) %>% 
  summarize(mean = mean(value, na.rm = T)) %>% 
  pivot_wider(names_from = "measurement", values_from = "mean")
## # A tibble: 130 × 4
## # Groups:   year [26]
##     year plot_type                 hindfoot_length weight
##    <dbl> <chr>                               <dbl>  <dbl>
##  1  1977 Control                              36.1   50.4
##  2  1977 Long-term Krat Exclosure             33.7   34.8
##  3  1977 Rodent Exclosure                     39.1   48.2
##  4  1977 Short-term Krat Exclosure            35.8   41.3
##  5  1977 Spectab exclosure                    37.2   47.1
##  6  1978 Control                              38.1   70.8
##  7  1978 Long-term Krat Exclosure             22.6   35.9
##  8  1978 Rodent Exclosure                     37.8   67.3
##  9  1978 Short-term Krat Exclosure            36.9   63.8
## 10  1978 Spectab exclosure                    42.3   80.1
## # ℹ 120 more rows

Exporting data

Now that you have learned how to use dplyr to extract information from or summarize your raw data, you may want to export these new data sets to share them with your collaborators or for archival.

Similar to the read_csv() function used for reading CSV files into R, there is a write_csv() function that generates CSV files from data frames.

Before using write_csv(), we are going to create a new folder, data, in our working directory that will store this generated dataset. We don’t want to write generated datasets in the same directory as our raw data. It’s good practice to keep them separate. The data_raw folder should only contain the raw, unaltered data, and should be left alone to make sure we don’t delete or modify it. In contrast, our script will generate the contents of the data directory, so even if the files it contains are deleted, we can always re-generate them.

In preparation for our next lesson on plotting, we are going to prepare a cleaned up version of the data set that doesn’t include any missing data.

Let’s start by removing observations of animals for which weight and hindfoot_length are missing, or the sex has not been determined:

surveys_complete <- surveys %>% 
  filter(!is.na(weight),
         !is.na(hindfoot_length),
         !is.na(sex))

Because we are interested in plotting how species abundances have changed through time, we are also going to remove observations for rare species (i.e., that have been observed less than 50 times). We will do this in two steps: first we are going to create a data set that counts how often each species has been observed, and filter out the rare species; then, we will extract only the observations for these more common species:

# Extract the most common species_id
species_counts <- surveys_complete %>% 
  count(species_id) %>% 
  filter(n >= 50)

# Keep only the most common species
surveys_complete <- surveys_complete %>% 
  filter(species_id %in% species_counts$species_id)

To make sure that everyone has the same data set, check that surveys_complete has 30463 rows and 13 columns by typing dim(surveys_complete).

dim(surveys_complete)
## [1] 30463    13

Now that our data set is ready, we can save it as a CSV file in our data folder.

write_csv(surveys_complete, path = "data/surveys_complete.csv")

Okay, this was a lot! Fortunately, you do not need to memorize all the functions at once. You can always refer back to this lesson or to the dplyr and tidyr cheatsheets (available on Brightspace) for the functions you need to accomplish what you want with your data.